document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=602114>Question 602114</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the expression tan(-220) is equivalent to?<BR>\n" );
document.write( "a)  tan 50<BR>\n" );
document.write( "b) -tan 50<BR>\n" );
document.write( "c) -tan 40 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #380126 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=380126\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the expression tan(-220) is equivalent to?<BR>\n" );
document.write( "----<BR>\n" );
document.write( "-220 = +140 is in Q2 where the tangent is negative<BR>\n" );
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document.write( "The reference angle for -220 is 40 degrees<BR>\n" );
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document.write( "t(-220) = -tan(40)<BR>\n" );
document.write( "a) tan 50<BR>\n" );
document.write( "b) -tan 50<BR>\n" );
document.write( "c) -tan 40<BR>\n" );
document.write( "==================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );