document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=602068>Question 602068</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello. I could really use some help on this word problem. If I could set up the equation I could solve it but I am having trouble. Please help.\r<BR>\n" );
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document.write( "Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 80 mph and train B is traveling at 90 mph. Train A passes a station at 9:20 P.M. If train B passes the same station at 9:32 P.M., what time will train B catch up to train A? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #380101 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=380101\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A has a 12 min lead on B ___ 12 min is 1/5 hr (12/60)\r<BR>\n" );
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document.write( "A is traveling 80 mph, so 1/5 hr is 16 mi (80 * 1/5)\r<BR>\n" );
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document.write( "B is catching A at 10 mph (90 - 80)\r<BR>\n" );
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document.write( "it will take B 1.6 hr to catch A (16 / 10) ___ this is from the time that B passes the station\r<BR>\n" );
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document.write( "equation-wise; the distances are equal when B catches up, and A has 1/5 hr head start\r<BR>\n" );
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document.write( "90t = 80(t + 1/5)\r<BR>\n" );
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document.write( "the question asks what time, so t must be added to 9:32 PM </SPAN>\n" );
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