document.write( "Question 602068: Hello. I could really use some help on this word problem. If I could set up the equation I could solve it but I am having trouble. Please help.\r
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document.write( "Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 80 mph and train B is traveling at 90 mph. Train A passes a station at 9:20 P.M. If train B passes the same station at 9:32 P.M., what time will train B catch up to train A? \n" );
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Algebra.Com's Answer #380099 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! How much of a head start does train A have? The \n" ); document.write( "head start is from 9:20 to 9:32, which is 12 minutes. \n" ); document.write( "In 12 minutes, train A travels \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "-------------------- \n" ); document.write( "Now start a stopwatch when train B leaves the station. \n" ); document.write( "Both trains will travel for the same amount of time \n" ); document.write( "until they meet. \n" ); document.write( "Let the time until they meet = \n" ); document.write( "Let the distance that train B has to travel = \n" ); document.write( "-------------------- \n" ); document.write( "Equation for A: \n" ); document.write( "(1) \n" ); document.write( "Equation for B: \n" ); document.write( "(2) \n" ); document.write( "-------------- \n" ); document.write( "Substitute (2) into (1) \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( " \n" ); document.write( "B will catch up to A 1 hour and 36 minutes after \n" ); document.write( "9:32, which is 11:08 PM\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |