document.write( "Question 602068: Hello. I could really use some help on this word problem. If I could set up the equation I could solve it but I am having trouble. Please help.\r
\n" ); document.write( "\n" ); document.write( "Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 80 mph and train B is traveling at 90 mph. Train A passes a station at 9:20 P.M. If train B passes the same station at 9:32 P.M., what time will train B catch up to train A?
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Algebra.Com's Answer #380099 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
How much of a head start does train A have? The
\n" ); document.write( "head start is from 9:20 to 9:32, which is 12 minutes.
\n" ); document.write( "In 12 minutes, train A travels
\n" ); document.write( "\"+80%2A%2812%2F60%29+=+80%2F5+\"
\n" ); document.write( "\"+80%2F5+=+16+\" miles ( note that 12 min is 12/60 hours )
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\n" ); document.write( "Now start a stopwatch when train B leaves the station.
\n" ); document.write( "Both trains will travel for the same amount of time
\n" ); document.write( "until they meet.
\n" ); document.write( "Let the time until they meet = \"+t+\" hours
\n" ); document.write( "Let the distance that train B has to travel = \"+d+\"
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\n" ); document.write( "Equation for A:
\n" ); document.write( "(1) \"+d+-+16+=+80t+\"
\n" ); document.write( "Equation for B:
\n" ); document.write( "(2) \"+d+=+90t+\"
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\n" ); document.write( "Substitute (2) into (1)
\n" ); document.write( "(1) \"+90t+-+16+=+80t+\"
\n" ); document.write( "(1) \"+10t+=+16+\"
\n" ); document.write( "(1) \"+t+=+1.6+\" hrs
\n" ); document.write( "\"+.6%2A60+=+36+\" minutes
\n" ); document.write( "B will catch up to A 1 hour and 36 minutes after
\n" ); document.write( "9:32, which is 11:08 PM\r
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