document.write( "Question 601936: 6x − 3y = 18\r
\n" ); document.write( "\n" ); document.write( "6x + 3y = −12\r
\n" ); document.write( "\n" ); document.write( "Solve using substitution
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Algebra.Com's Answer #380063 by flame8855(424)\"\" \"About 
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6x − 3y = 18
\n" ); document.write( "6x + 3y = −12
\n" ); document.write( "2x-y=6
\n" ); document.write( "y=2x-6
\n" ); document.write( "6x+3y=-12
\n" ); document.write( "6x+3(2x-6)=-12
\n" ); document.write( "6x+6x-18=-12
\n" ); document.write( "12x=6
\n" ); document.write( "x=1/2
\n" ); document.write( "y=-5
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