document.write( "Question 55943: Could you please help me solve, sqrt(2+4x) + sqrt(3-4x)=3\r
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Algebra.Com's Answer #38005 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
sqrt(2+4x) + sqrt(3-4x)=3
\n" ); document.write( "Square both sides to get:
\n" ); document.write( "2+4x + 2sqrt[(2+4x)(3-4x)] + 3-4x = 9
\n" ); document.write( "5 + 2sqrt[6+4x-16x^2] = 9
\n" ); document.write( "sqrt[6+4x-16x^2] =2
\n" ); document.write( "Square both sides again:
\n" ); document.write( "6+4x-16x^2= 4
\n" ); document.write( "16x^2-4x-2=0
\n" ); document.write( "(2x-1)(8x+2)=0
\n" ); document.write( "x=1/2 or x=1/4
\n" ); document.write( "Checking these answers in the original problem:
\n" ); document.write( "If x=1/2, sqrt(2+2) + sqrt(3-2)=3
\n" ); document.write( "True
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\n" ); document.write( "If x=1/4, sqrt(2+1) + sqrt(3-1)=3
\n" ); document.write( "False
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\n" ); document.write( "The only solution is x=1/2
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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