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Algebra.Com's Answer #380044 by mananth(16949)![\"\"](\"/images/stars/stars-13.gif\")  You can put this solution on YOUR website! 6x+8y=14\r \n" ); document.write( "\n" ); document.write( "xy=-12\r \n" ); document.write( "\n" ); document.write( "x=-12/y\r \n" ); document.write( "\n" ); document.write( "substitute x \n" ); document.write( "6*(-12/y) +8y=14\r \n" ); document.write( "\n" ); document.write( "multiply the equation by y \n" ); document.write( "-72 +8y^2=14y\r \n" ); document.write( "\n" ); document.write( "8y^2-14y-72=0 \n" ); document.write( "/2 \n" ); document.write( "4y^2-7y-36=0 \n" ); document.write( "4y^2-7y-36=0 \n" ); document.write( " \n" ); document.write( "You have to factorize . convert the trinomial into a a polynomial with 4 terms by splitting the middle term. \n" ); document.write( "compare with equation ax^2 +bx+c \n" ); document.write( "co-efficient of 1st term - a=4 \n" ); document.write( "co-efficient of second term = b= -7 \n" ); document.write( "co-eficient of third term = -36 \n" ); document.write( " \n" ); document.write( "The product ac= 4*-36 = -144 \n" ); document.write( "factorize -144 . \n" ); document.write( "group the factors into parts, such that the sum of I part & II part = -7 \n" ); document.write( "-144= -2*2*2*2* 3*3 \n" ); document.write( " \n" ); document.write( "-16 & 9 are the factors add them you get -7 \n" ); document.write( "multiply them you get -144 \n" ); document.write( " \n" ); document.write( "4y^2-16y+9y-36=0 \n" ); document.write( "49(y-4)+9(y-4)=0 \n" ); document.write( "(y-4)(4y+9)=0 \n" ); document.write( "y = 4 Or -9/4\r \n" ); document.write( "\n" ); document.write( "plug y in xy =-12 to get x= 3 Or x= 16/3 \n" ); document.write( " |