document.write( "Question 601862: mr.hart made two investments, one at 4.5% and the other at 3%. the amount invested at 3% exceeded the amount invested at 4.5% by $300. if his total annual income was $84, find the amount invested at each rate. \n" ); document.write( "
Algebra.Com's Answer #380041 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! mr.hart made two investments, one at 4.5% and the other at 3%. the amount invested at 3% exceeded the amount invested at 4.5% by $300. if his total annual income was $84, find the amount invested at each rate. \n" ); document.write( ". \n" ); document.write( "Let x = amount ($) invested at 4.5% \n" ); document.write( "then \n" ); document.write( "x+300 = amount ($) invested at 3% \n" ); document.write( ". \n" ); document.write( ".045x + .03(x+300) = 84 \n" ); document.write( ".045x + .03x+9 = 84 \n" ); document.write( ".075x+9 = 84 \n" ); document.write( ".075x = 75 \n" ); document.write( "x = $1000 (invested at 4.5%) \n" ); document.write( ". \n" ); document.write( "invested at 3%: \n" ); document.write( "x+300 = 1000+300 = $1300 \n" ); document.write( " \n" ); document.write( " |