document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=56035>Question 56035</A>: <I><SPAN STYLE=\"word-break: break-all;\"> -6w-12-3w+2  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #37996 by </B><A HREF=/tutors/aboutme.mpl?userid=koolchick><B>koolchick(3)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=koolchick><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=37996\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> what your going to have to do is group like terms into parenthesis<BR>\n" );
document.write( "            (-6w)-12-(3w)+2 <BR>\n" );
document.write( "   add the two numbers that have the like terms -6 and 3w you will get  a 9 <BR>\n" );
document.write( "              then you subtract 12 and 2 you will get a ten, so after all its 9w minus 10 good luck!!    <BR>\n" );
document.write( "                =-9w-10 </SPAN>\n" );
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