document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=601688>Question 601688</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A coin is tossed three times find the probability that .exactly one tail turns up .at least two tail turn up .no tail turn up. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #379946 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=379946\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A coin is tossed three times <BR>\n" );
document.write( "Binomial Problems with n = 3 and p(tail) = 1/2<BR>\n" );
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document.write( "find the probability that \r<BR>\n" );
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document.write( ".exactly one tail turns up<BR>\n" );
document.write( "P(x = 1) = 3C1(1/2)(1/2)^2 = 3/8<BR>\n" );
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document.write( ".at least two tail turn up<BR>\n" );
document.write( "P(x = 2 or x = 3) = 3C2(1/2)^2(1/2) + 3C3(1/2)^3*(1/2)^0<BR>\n" );
document.write( "= 3/8 + 1/8 = 4/8 = 1/2<BR>\n" );
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document.write( ".no tail turn up.<BR>\n" );
document.write( "P(x = 0) = 3C0(1/2)^0*(1/2)^3 = 1/8<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
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