document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=56031>Question 56031</A>: <I><SPAN STYLE=\"word-break: break-all;\"> -6w-12-3w=+2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #37994 by </B><A HREF=/tutors/aboutme.mpl?userid=Lacey020991><B>Lacey020991(49)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Lacey020991><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=37994\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Goal: to isolate w by it's self to determine the value.<BR>\n" );
document.write( "You would combine like terms first<BR>\n" );
document.write( "-6w - 12 - 3w = 2<BR>\n" );
document.write( "-9w - 12 = 2 ----add 12 to both sides<BR>\n" );
document.write( "-9w = 14 --------divide each side by -9<BR>\n" );
document.write( "w = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-1%282%2F3%29 ALIGN=MIDDLE  ALT=\"-1%282%2F3%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "or w = -1.5557\r<BR>\n" );
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document.write( "i hope this is what you needed! if not let me know.  <BR>\n" );
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