document.write( "Question 601539: Please help me solve this:
\n" ); document.write( "how much canvas is needed to make an A-frame tent that is 4ft high with a rectangular floor 6ft wide and 9ft long? \n" ); document.write( "

Algebra.Com's Answer #379891 by KMST(5328) $\"\"$ $\"About$

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The front of the tent would look like this:
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made of 2 right triangles with leg lengths of 3 feet and 4 feet.
\n" ); document.write( "The area of each triangle (in square feet) is
\n" ); document.write( " $\"%281%2F2%29%2A3%2A4=6\"$ so the front requires at least 12 square feet of canvas.
\n" ); document.write( "The back will also require 12 square feet of canvas.
\n" ); document.write( "The hypotenuse of those right triangles has a length (in feet) of $\"x\"$ and
\n" ); document.write( " $\"x%5E2=3%5E2%2B4%5E2=9%2B16=23\"$ according to Pythagoras theorem.
\n" ); document.write( "So $\"x=sqrt%2823%29\"$ or about 4.8 feet.
\n" ); document.write( "The pieces that form the roof will have that width and a length of 9 feet.
\n" ); document.write( "So the amount of canvas needed for the roof (in square feet) is
\n" ); document.write( " $\"2%2A%28sqrt%2823%29%2A9%29=2%2A9%2Asqrt%2823%29=18%2Asqrt%2823%29\"$
\n" ); document.write( "That must be added to the
\n" ); document.write( " $\"2%2A12%29\"$ square feet of canvas = 24 square feet of canvas for front and back.
\n" ); document.write( "For the mathematically exact answer, you will need
\n" ); document.write( " $\"24%2B18%2Asqrt%2823%29\"$ square feet of canvas (about 110.325 square feet of canvas).
\n" ); document.write( "Of course, the practical answer will be that you need more for seams and flaps, and whatnot.\r
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