document.write( "Question 601549: a mixture is prepared by mixing 50 grams of ethanol, 50 grams of water , and 5 grams sugar.
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\n" ); document.write( "what is the mass percent of each component in the mixture.\r
\n" ); document.write( "\n" ); document.write( "how many grams of the mixture should one take in order to have 1.5 grams sugar.\r
\n" ); document.write( "\n" ); document.write( "how many grams of the mixture should one take in order to have 10 grams of alcohol?
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Algebra.Com's Answer #379856 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Total grams of mixture =
\n" ); document.write( "\"+50+%2B+50+%2B+5+=+105+\"
\n" ); document.write( "alcohol:
\n" ); document.write( "\"+50%2F105+=+.4762+\"
\n" ); document.write( "47.62%
\n" ); document.write( "water:
\n" ); document.write( "47.62%
\n" ); document.write( "sugar:
\n" ); document.write( "\"+5%2F105+=+.04762+\"
\n" ); document.write( "4.762%
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\n" ); document.write( "Let \"+x+\" = grams of mixture that you take
\n" ); document.write( "\"+.04762x+=+1.5+\"
\n" ); document.write( "\"+x+=+1.5%2F.04762+\"
\n" ); document.write( "\"+x+=+31.5+\"
\n" ); document.write( "You must take 31.5 grams of the mixture
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\n" ); document.write( "\"+.4762x+=+10+\"
\n" ); document.write( "\"+x+=+10%2F.4762+\"
\n" ); document.write( "\"+x+=+21+\"
\n" ); document.write( "You must take 21 grams of the mixture
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