document.write( "Question 601545: One number is five more than a first number. A third number is four times the first number. If the sum of the three numbers is 323, find each of the numbers \n" ); document.write( "
Algebra.Com's Answer #379847 by Rcmathtutor(12)\"\" \"About 
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Let first number = x, second number = y and third number = z
\n" ); document.write( "1) y = x + 5
\n" ); document.write( "2) z = 4x
\n" ); document.write( "3) x + y + z = 323
\n" ); document.write( "Substitute y and z in equation #3:
\n" ); document.write( "x + x + 5 + 4x = 323
\n" ); document.write( "6x + 5 = 323
\n" ); document.write( "6x = 318
\n" ); document.write( "x = 53
\n" ); document.write( "Substitute x in equation #1:
\n" ); document.write( "y = 53 + 5
\n" ); document.write( "y = 58
\n" ); document.write( "Substitute x in equation #2:
\n" ); document.write( "z = 4(53)
\n" ); document.write( "z = 212
\n" ); document.write( "The numbers are: 53, 58 and 212.\r
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