document.write( "Question 6924: 1/2 kids have left party
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document.write( "18 kids are standing around
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document.write( "1/3 are dancing
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document.write( "how many kids were originally at party \n" );
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Algebra.Com's Answer #3798 by glabow(165) ![]() You can put this solution on YOUR website! I get a different answer. \n" ); document.write( "Let x be the number of kids originally at the party. \n" ); document.write( "Then after half leave, x/2 remain. \n" ); document.write( "Of these, 1/3 are dancing. That is, x/6 are dancing. \n" ); document.write( "18 are just standing around. \n" ); document.write( "So, x/6 + 18 = x/2 \n" ); document.write( "Solving, \n" ); document.write( "x/6 - x/2 = -18 \n" ); document.write( "x/6 - 3x/6 = -18 \n" ); document.write( "x - 3x = -108 \n" ); document.write( "-2x = -108 \n" ); document.write( "x= 54 \n" ); document.write( "There were orginally 54 kids. Half left, leaving 27. Of these, 1/3 are dancing = 9. The remaining 18 are standing around. \n" ); document.write( " |