document.write( "Question 601453: This problem is 8x squared minus 3 equals 10x or 8x^2-3=10x
\n" ); document.write( "Then it says solve. Please help. Thank you. I feel like I should get everything on one side and set it to 0 but, from there on I'm not sure what to do.
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Algebra.Com's Answer #379767 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
This problem is 8x squared minus 3 equals 10x or 8x^2-3=10x
\n" ); document.write( "Then it says solve. Please help. Thank you. I feel like I should get everything on one side and set it to 0 but, from there on I'm not sure what to do.
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\n" ); document.write( "That is step 1.
\n" ); document.write( "\"8x%5E2+-+10x+-+3+=+0\"
\n" ); document.write( "Then you can factor it.
\n" ); document.write( "(2x - 3)*(4x + 1) = 0
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\n" ); document.write( "2x-3 = 0
\n" ); document.write( "x = 3/2
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\n" ); document.write( "4x+1 = 0
\n" ); document.write( "x = -1/4
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\n" ); document.write( "If it can't be factored, use the quadratic equation
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Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"8x%5E2%2B-10x%2B-3+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%28-10%29%5E2-4%2A8%2A-3=196\".
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\n" ); document.write( " Discriminant d=196 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28--10%2B-sqrt%28+196+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%28-10%29%2Bsqrt%28+196+%29%29%2F2%5C8+=+1.5\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%28-10%29-sqrt%28+196+%29%29%2F2%5C8+=+-0.25\"
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\n" ); document.write( " Quadratic expression \"8x%5E2%2B-10x%2B-3\" can be factored:
\n" ); document.write( " \"8x%5E2%2B-10x%2B-3+=+%28x-1.5%29%2A%28x--0.25%29\"
\n" ); document.write( " Again, the answer is: 1.5, -0.25.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+8%2Ax%5E2%2B-10%2Ax%2B-3+%29\"

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