document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=56004>Question 56004</A>: <I><SPAN STYLE=\"word-break: break-all;\"> THE LENGTH OF A RECTANGLE IS 3IN MORE THAT TWICE IT'S WIDTH. iF THE PEREMETER OF THE RECATNGLE IS 36 INC FIND THE WIDTH OF THE RECTANGLE.\r<BR>\n" );
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document.write( "tHANK YOU SOOOO MUCH. yOU ALL HAVE HELPED ME SO MUCH </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #37971 by </B><A HREF=/tutors/aboutme.mpl?userid=Lacey020991><B>Lacey020991(49)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Lacey020991><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=37971\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The length of the rectangle (l) = 2w+3  (twice the width plus 3 in)<BR>\n" );
document.write( "The width of the rectangle (w) = w\r<BR>\n" );
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document.write( "l = 2w+3<BR>\n" );
document.write( "w = w\r<BR>\n" );
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document.write( "P = 2l + 2w<BR>\n" );
document.write( "36 = 2(2w+3) + 2w ++++++ distribute the 2<BR>\n" );
document.write( "36 = 4w + 6 + 2w +++++++ combine like terms<BR>\n" );
document.write( "36 = 6w + 6 ++++++++++++ subtract 6 from each side<BR>\n" );
document.write( "30 = 6w ++++++++++++++++ divide each side by 6<BR>\n" );
document.write( "5 = w\r<BR>\n" );
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document.write( "The width of the rectangle would be 5<BR>\n" );
document.write( "The length would be 13 </SPAN>\n" );
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