document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=601325>Question 601325</A>: <I><SPAN STYLE=\"word-break: break-all;\">  if y is proportional to 2x-7,and y=-9 when x=2,find x when y=-15.Please show me step by step. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #379697 by </B><A HREF=/tutors/aboutme.mpl?userid=flame8855><B>flame8855(424)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=flame8855><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=flame8855><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=379697\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> since y is proportional to 2x-7 then y= k(2x-7)<BR>\n" );
document.write( "when x = 2 , y= -9<BR>\n" );
document.write( "-9=k(4-7)<BR>\n" );
document.write( "k= 3<BR>\n" );
document.write( "so y=3(2x-7)<BR>\n" );
document.write( "when y= -15<BR>\n" );
document.write( "-15=3(2x-7)<BR>\n" );
document.write( "2x-7=-5<BR>\n" );
document.write( "x=1<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );