document.write( "Question 601251: A rectangle has an area of 190 cm and a perimeter of 58 cm. What are its dimensions? \n" ); document.write( "
Algebra.Com's Answer #379661 by mananth(16946)![]() ![]() You can put this solution on YOUR website! length = l \n" ); document.write( "width = w \n" ); document.write( "l*w = 190\r \n" ); document.write( "\n" ); document.write( "2(l+w)= 58 \n" ); document.write( "/2 \n" ); document.write( "(l+w)= 29\r \n" ); document.write( "\n" ); document.write( "l= 190/w\r \n" ); document.write( "\n" ); document.write( "190/w + w = 29\r \n" ); document.write( "\n" ); document.write( "multiply equation by w\r \n" ); document.write( "\n" ); document.write( "190+w^2=29w \n" ); document.write( "w^2-29w+190=0 \n" ); document.write( "w^2-19w-10w+190\r \n" ); document.write( "\n" ); document.write( "w(w-19)-10(w-19)=0 \n" ); document.write( "(w-19)(w-10)=0 \n" ); document.write( "w= 19 OR 10\r \n" ); document.write( "\n" ); document.write( "The length = 19 cm width = 10cm \n" ); document.write( " |