document.write( "Question 601238: Pure tin was mixed with an 8% tin alloy to produce an alloy that was 25% tin. How much pure tin and how much 8% alloy were used to produce 184 Kg of 25%alloy. \n" ); document.write( "
Algebra.Com's Answer #379657 by mananth(16946)\"\" \"About 
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percent ---------------- quantity
\n" ); document.write( "Pure Tin 100.00% ---------------- x kg
\n" ); document.write( "Tin impure 8.00% ------ 184 - x kg
\n" ); document.write( "Mixture 25.00% ---------------- 184
\n" ); document.write( " 12
\n" ); document.write( "100.00% x+8.00%( 184-x)= 25.00%* 184
\n" ); document.write( "100x+8(184-x)=4600
\n" ); document.write( "100x+1472-8x=4600
\n" ); document.write( "100x-8x= 4600 - (-1472 )
\n" ); document.write( "92x=3128
\n" ); document.write( "/ 92
\n" ); document.write( "x=34kg 100.00% Pure Tin
\n" ); document.write( "150kg 8.00% Tin impure
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\n" ); document.write( "m.ananth@hotmail.ca
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