document.write( "Question 601229: i cant get the answer for this one please help me.\r
\n" ); document.write( "\n" ); document.write( "express cos 136 degrees as a function of a positive acute angle \n" ); document.write( "
Algebra.Com's Answer #379654 by Edwin McCravy(20060)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "The other tutor gave you a correct answer, but he gave it as a sine\r\n" );
document.write( "function of the complement of the reference angle, instead of \r\n" );
document.write( "a cosine function of the reference angle.  I think you should \r\n" );
document.write( "express it as a cosine function of the reference angle, since \r\n" );
document.write( "you were given a cosine function, not change to different trig \r\n" );
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document.write( "Rules for finding the reference angle:\r\n" );
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document.write( "If an angle is between 0° and 90° (Quadrant I), the reference angle\r\n" );
document.write( "is the same as the angle.\r\n" );
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document.write( "If an angle is between 90° and 180° (Quadrant II), to find the reference \r\n" );
document.write( "angle, subtract it from 180°.\r\n" );
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document.write( "If an angle is between 180° and 270° (Quadrant III), to find the reference \r\n" );
document.write( "angle, subtract 180° from it.\r\n" );
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document.write( "If an angle is between 270° and 360° (Quadrant IV), to find the reference \r\n" );
document.write( "angle, subtract it from 360°.\r\n" );
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document.write( "So the reference angle for 136° (Quadrant II), is 180°-136° = 44°\r\n" );
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document.write( "Since the cosine is negative in Quadrant II, the answer is \r\n" );
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document.write( "-cos(44°)\r\n" );
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document.write( "That is what I believe your teacher wants, not a sine function of\r\n" );
document.write( "the complement of the reference angle.\r\n" );
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document.write( "Edwin
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