document.write( "Question 601233: (x+10)(x-17)(x+7)>0 \n" ); document.write( "

Algebra.Com's Answer #379652 by josmiceli(19441) $\"\"$ $\"About$

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When $\"+x+\"$ is a positive number, the middle term
\n" ); document.write( "cannot be negative or zero.
\n" ); document.write( "Therefore, $\"+x+%3E17+\"$
\n" ); document.write( "------------------
\n" ); document.write( "If $\"+x+\"$ is a negative number, then the middle term
\n" ); document.write( "will always be negative, and one of the other terms must
\n" ); document.write( "also be negative.
\n" ); document.write( " $\"+x+%3C+-7+\"$ , but $\"+x+\"$ cannot be less than $\"+-10+\"$
\n" ); document.write( "because then I have (-)x(-)x(-) = (-)
\n" ); document.write( " $\"+-10+%3C+x+%3C+-7+\"$
\n" ); document.write( "---------------
\n" ); document.write( "These are the conditions for th inequality to be true:
\n" ); document.write( " $\"+x+%3E17+\"$
\n" ); document.write( " $\"+-10+%3C+x+%3C+-7+\"$
\n" ); document.write( " \n" ); document.write( "

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