document.write( "Question 601236: Pure copper was mixed with a 12% copper alloy to produce an alloy that was 32% copper. How much of the pure copper and how much 12% alloy were used to produce 44 Kg of 32% alloy? \n" ); document.write( "
Algebra.Com's Answer #379648 by mananth(16946)\"\" \"About 
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percent ---------------- quantity
\n" ); document.write( "Pure Copper 100.00% ---------------- x kg
\n" ); document.write( "Copper Alloy 12.00% ------ 44 - x kg
\n" ); document.write( "Mixture 32.00% ---------------- 44
\n" ); document.write( " 12
\n" ); document.write( "100.00% x+12.00% (44-x)=32.00%*44
\n" ); document.write( "100x+12(44-x)=1408
\n" ); document.write( "100x+528 -12x=1408
\n" ); document.write( "100x-12 x =1408-528
\n" ); document.write( "88x= 880
\n" ); document.write( "/ 88
\n" ); document.write( "x=10kg 100.00% Pure Copper
\n" ); document.write( "34 kg 12.00% Copper Alloy
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\n" ); document.write( "m.ananth@hotmail.ca
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