document.write( "Question 600971: help me solve this question\r
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Algebra.Com's Answer #379579 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "\"++sqrt+%28+%283n-5%29%2F%28n%2B1%29+%29\"\r\n" );
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document.write( "In order for that to equal to an integer,\r\n" );
document.write( "what's under the radical must be a perfect square. \r\n" );
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document.write( "We compare the fraction \"%283n-5%29%2F%28n%2B1%29\" to the fraction\r\n" );
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document.write( "\"3n%2Fn\", and observe that \"%283n-5%29%2F%28n%2B1%29\" has a smaller \r\n" );
document.write( "numerator and a larger denominator than \"3n%2Fn%7D%7D+so+it%27s+less+%0D%0Athan+%7B%7B%7B3n%2Fn\" which is 3. So \"++%283n-5%29%2F%28n%2B1+%29\" is a perfect\r\n" );
document.write( "square less than 3. \r\n" );
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document.write( "The only perfect square less than 3 is 1, so what's under the \r\n" );
document.write( "radical must equal to 1.  So\r\n" );
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document.write( "\"+%283n-5%29%2F%28n%2B1%29+\" = 1\r\n" );
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document.write( "Multiply both sides by n+1\r\n" );
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document.write( "3n - 5 = n + 1\r\n" );
document.write( "    2n = 6\r\n" );
document.write( "     n = 3\r\n" );
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document.write( "So n=3 and therefore\r\n" );
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document.write( "\"++sqrt+%28+%283n-5%29%2F%28n%2B1%29+%29\" = \"++sqrt+%28+%283%283%29-5%29%2F%28%283%29%2B1%29+%29\" = \"++sqrt+%28+%289-5%29%2F%283%2B1%29+%29\" = \"4%2F4\" = 1\r\n" );
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document.write( "Edwin
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