document.write( "Question 600952: Write the rational expression 7/2x^2-5x-3 as a sum of partial fractions. \n" ); document.write( "
Algebra.Com's Answer #379577 by ankor@dixie-net.com(22740)\"\" \"About 
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Write the rational expression 7/2x^2-5x-3 as a sum of partial fractions.
\n" ); document.write( "Factor the denominator and write it
\n" ); document.write( "\"7%2F%28%282x%2B1%29%28x-3%29%29\" = \"A%2F%28%282x%2B1%29%29\" + \"B%2F%28%28x-3%29%29\"
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\n" ); document.write( "Combine the fractions on the right
\n" ); document.write( "\"7%2F%28%282x%2B1%29%28x-3%29%29\" = \"%28A%28x-3%29%2BB%282x%2B1%29%29%2F%28%282x%2B1%29%28x-3%29%29\"
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\n" ); document.write( "If the denominators are equal, the numerators are, we can write it
\n" ); document.write( "7 = A(x-3) + B(2x+1)
\n" ); document.write( ":
\n" ); document.write( "Assume this is an identity, equation true for all values of x.
\n" ); document.write( "Let x=3
\n" ); document.write( "7 = A(3-3) + B(2(3)+1)
\n" ); document.write( "The A term drops out
\n" ); document.write( "7 = 7B + 0
\n" ); document.write( "B = 1
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\n" ); document.write( "Let x=-.5
\n" ); document.write( "7 = A(-.5-3) + B(2(-.5)+1)
\n" ); document.write( "The B term drops out
\n" ); document.write( "7 = -3.5A + 0
\n" ); document.write( "A = -2
\n" ); document.write( ":
\n" ); document.write( "The decomposed fraction
\n" ); document.write( "\"7%2F%28%282x%2B1%29%28x-3%29%29\" = \"%28-2%29%2F%28%282x%2B1%29%29\" + \"1%2F%28%28x-3%29%29\"\r
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