document.write( "Question 600886: A plane is flying at an altitude of about 7 miles above Earth. What is the measure of the arc that represents the part of Earth you can see? The radius of Earth is about 4000 miles. Please help me. I have tried to do this problem many times but the concept confuses me. Thank you. \n" ); document.write( "
Algebra.Com's Answer #379542 by ankor@dixie-net.com(22740)\"\" \"About 
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A plane is flying at an altitude of about 7 miles above Earth.
\n" ); document.write( " What is the measure of the arc that represents the part of Earth you can see? The radius of Earth is about 4000 miles.
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\n" ); document.write( "Perhaps we can treat this as a \"distance to horizon\" problem, the observer is 7 mi above the earth
\n" ); document.write( "One formula is: \"d+=+sqrt%28%283h%29%2F2%29\" where d is in miles and h is in feet
\n" ); document.write( "Change 7 mi; 5280*7 = 36960 ft
\n" ); document.write( "so we have
\n" ); document.write( "d = \"sqrt%28%283960%2A3%29%2F2%29\"
\n" ); document.write( "d ~ 235.5 mi
\n" ); document.write( "looking in opposite directions a total of 2*235 = 471 mi can be viewed
\n" ); document.write( "Find the circumference of the earth
\n" ); document.write( "C = \"pi%2A8000\"
\n" ); document.write( "C = 25133 mi
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\n" ); document.write( "The arc: \"471%2F25133\" * 360 = 6.7 degrees
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\n" ); document.write( "This should be pretty close, because the earth is so large compared to the altitude. would appreciate if it you would let me know. C
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