document.write( "Question 600928: 3x-5y=15x2
\n" ); document.write( "2x+3y=6x3
\n" ); document.write( "6x-10y=30......(1)
\n" ); document.write( "6x+9y=18.......(2)
\n" ); document.write( "subtracting (2) from (1) we get
\n" ); document.write( "-19y=12
\n" ); document.write( "y=-12/19
\n" ); document.write( "substituting value of y in equation (1) we get
\n" ); document.write( "3x-5y=15
\n" ); document.write( "3x-5(-12/19)=15
\n" ); document.write( "3x=15-5(12/19)
\n" ); document.write( "3x=(19x15-5x12)/19
\n" ); document.write( "3x=(285-60)/19
\n" ); document.write( "3x=225/19
\n" ); document.write( "x=75/19\r
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Algebra.Com's Answer #379540 by smh905(1)\"\" \"About 
You can put this solution on YOUR website!
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