document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=600881>Question 600881</A>: <I><SPAN STYLE=\"word-break: break-all;\"> THE AREA OF THE CIRCLE IS 676(PIE SIGN) SQUARE CENTIMETERS. FIND THE DIAMETER  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #379525 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=379525\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A = pi*r^2\r<BR>\n" );
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document.write( "676pi = pi*r^2\r<BR>\n" );
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document.write( "676pi/pi = (pi*r^2)/pi\r<BR>\n" );
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document.write( "676 = r^2\r<BR>\n" );
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document.write( "r^2 = 676\r<BR>\n" );
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document.write( "r = sqrt(676)\r<BR>\n" );
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document.write( "r = 26\r<BR>\n" );
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document.write( "The radius is 26 cm. So the diameter is d = 2r = 2*26 = <font color=\"red\">52 cm</font> </SPAN>\n" );
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