document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=600799>Question 600799</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I can not understand how to factor trinomials in ax^2+bx+c format. I have been studying this for two weeks at school now. I understand the process, but I for some reason am horrible at this. Here is a problem I need help solving. \r<BR>\n" );
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document.write( "-4c^2+19c-21\r<BR>\n" );
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document.write( "I need to find the two numbers that equal the variable. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #379494 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=379494\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -4c^2+19c-21\r<BR>\n" );
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document.write( "a= -4, b= 19, c= -21 \r<BR>\n" );
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document.write( "ac= (-4*-8)= +84\r<BR>\n" );
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document.write( "factorise 84 <BR>\n" );
document.write( "84= 2*2*3*7\r<BR>\n" );
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document.write( "Try  a combination of these factors  to add up to b=19\r<BR>\n" );
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document.write( "2*2*3= 12 <BR>\n" );
document.write( "& 7<BR>\n" );
document.write( "12 & 7 are the factors\r<BR>\n" );
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document.write( "-4c^2+12c+7c-21=0\r<BR>\n" );
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document.write( "-4c(c-3)+7(c-3)<BR>\n" );
document.write( "(c-3)(7-4c) </SPAN>\n" );
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