document.write( "Question 600693: 1. SQR(x+20)=x
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document.write( "2.SQR(10x)-(2)SQR(5x-25)=0\r
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document.write( "Solve each of the following. Check for extraneous solutions.\r
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document.write( "What I know is; 1. x+20=x^2
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document.write( "That's as far as I know. I don't know how to check for extraneous solutions. \n" );
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Algebra.Com's Answer #379461 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! 1. SQR(x+20)=x \n" ); document.write( "2.SQR(10x)-(2)SQR(5x-25)=0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Solve each of the following. Check for extraneous solutions.\r \n" ); document.write( "\n" ); document.write( "What I know is; 1. x+20=x^2 \n" ); document.write( "That's as far as I know. I don't know how to check for extraneous solutions. \n" ); document.write( "------------ \n" ); document.write( "x+20=x^2 \n" ); document.write( " \n" ); document.write( "(x-5)*(x+4) = 0 \n" ); document.write( "x = -4 \n" ); document.write( "x = 5 \n" ); document.write( "------- \n" ); document.write( "Check each answer to see if it works. \n" ); document.write( "They both work --> no extraneous solutions. \n" ); document.write( "====================== \n" ); document.write( "2.SQR(10x)-(2)SQR(5x-25)=0 \n" ); document.write( "SQR(10x) = (2)SQR(5x-25) \n" ); document.write( "Square both sides \n" ); document.write( "10x = 4*(5x - 25) \n" ); document.write( "etc \n" ); document.write( " \n" ); document.write( " |