document.write( "Question 600693: 1. SQR(x+20)=x
\n" ); document.write( "2.SQR(10x)-(2)SQR(5x-25)=0\r
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\n" ); document.write( "\n" ); document.write( "Solve each of the following. Check for extraneous solutions.\r
\n" ); document.write( "\n" ); document.write( "What I know is; 1. x+20=x^2
\n" ); document.write( "That's as far as I know. I don't know how to check for extraneous solutions.
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Algebra.Com's Answer #379461 by Alan3354(69443)\"\" \"About 
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1. SQR(x+20)=x
\n" ); document.write( "2.SQR(10x)-(2)SQR(5x-25)=0\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Solve each of the following. Check for extraneous solutions.\r
\n" ); document.write( "\n" ); document.write( "What I know is; 1. x+20=x^2
\n" ); document.write( "That's as far as I know. I don't know how to check for extraneous solutions.
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\n" ); document.write( "x+20=x^2
\n" ); document.write( "\"x%5E2+-+x+-+20+=+0\"
\n" ); document.write( "(x-5)*(x+4) = 0
\n" ); document.write( "x = -4
\n" ); document.write( "x = 5
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\n" ); document.write( "Check each answer to see if it works.
\n" ); document.write( "They both work --> no extraneous solutions.
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\n" ); document.write( "2.SQR(10x)-(2)SQR(5x-25)=0
\n" ); document.write( "SQR(10x) = (2)SQR(5x-25)
\n" ); document.write( "Square both sides
\n" ); document.write( "10x = 4*(5x - 25)
\n" ); document.write( "etc
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