document.write( "Question 600444: a contractor got a contract to build a building in 30 days and employed 20 men to do the work. only 1/4 work was completed in 10 days. how many more men be employed so that the work be completed in the specified time? \n" ); document.write( "
Algebra.Com's Answer #379448 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! a contractor got a contract to build a building in 30 days and employed 20 men to do the work. only 1/4 work was completed in 10 days. how many more men be employed so that the work be completed in the specified time? \n" ); document.write( ": \n" ); document.write( "Find the number of man-hrs to complete 1/4 of the job \n" ); document.write( "20 * 10 = 200 man-days \n" ); document.write( "therefore \n" ); document.write( "3 * 200 = 600 man-days required to complete the job (For a total of 800 man-days) \n" ); document.write( ": \n" ); document.write( "Let m, = no. of additional men required to complete the job in the remaining 20 days \n" ); document.write( "20(m + 20) = 600 \n" ); document.write( "20m + 400 = 600 \n" ); document.write( "20m = 600 - 400 \n" ); document.write( "20m = 200 \n" ); document.write( "m = 200/20 \n" ); document.write( "m = 10 additional men required to finish the job in the required 30 days \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( " |