document.write( "Question 600676: at max speed, an airplane tavels 2100 miles aginst the wind in 6 hours. Flying with the wind, the plane can travel the same distance in 4 hours. what is the speed of the plane with no wind? \n" ); document.write( "
Algebra.Com's Answer #379428 by Edwin McCravy(20056)![]() ![]() You can put this solution on YOUR website! at max speed, an airplane tavels 2100 miles aginst the wind in 6 hours. Flying with the wind, the plane can travel the same distance in 4 hours. what is the speed of the plane with no wind? \n" ); document.write( " \r\n" ); document.write( "Let w = the speed of the wind\r\n" ); document.write( "Let p = the speed of the plane with no wind\r\n" ); document.write( "\r\n" ); document.write( "Then speed against the wind = (p-w)\r\n" ); document.write( "And speed with the wind = (p+w)\r\n" ); document.write( " \r\n" ); document.write( "\r\n" ); document.write( " distance = rate · time\r\n" ); document.write( "plane against wind 2100 = (p-w)· 6 \r\n" ); document.write( "plane with wind 2100 = (p+w)· 4\r\n" ); document.write( "\r\n" ); document.write( " 2100 = (p-w)·6\r\n" ); document.write( " 2100 = (p+w)·4\r\n" ); document.write( "\r\n" ); document.write( "Divide both sides of the first equation by 6\r\n" ); document.write( "Divide both sides of the second equation by 4\r\n" ); document.write( "\r\n" ); document.write( " 350 = p - w\r\n" ); document.write( " 525 = p + w\r\n" ); document.write( "\r\n" ); document.write( "Solve that system and get p = 437.5 mph, w = 87.5 mp\r\n" ); document.write( "\r\n" ); document.write( "Edwin \n" ); document.write( " \n" ); document.write( " |