document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=600613>Question 600613</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Ms. Payton consulted a pool manual to find the rate at which she should drain her swimming pool. The manual recommends that she drain the pool at a rate of 2500 liters per hour, but Ms Payton wants to know the rate in gallons per minute. If there are about 3.8 liters to a gallon, what is the rate in gallons per minute?\r<BR>\n" );
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document.write( "ASAP PLEASE HELP! I HAVE OTHER QUESTIONS FOR YOU TOO IF YOU HELP ME WITH THIS! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #379397 by </B><A HREF=/tutors/aboutme.mpl?userid=josmiceli><B>josmiceli(19441)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josmiceli><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=josmiceli><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=379397\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> In terms of units:<BR>\n" );
document.write( "( liters / hour ) x ( hours / minute ) x ( gallons / liter )<BR>\n" );
document.write( "Note that this is<BR>\n" );
document.write( "( liters/liters ) x ( hours/hours) x ( gallons / minute ) = gallons/minute<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+2500%2A%28+1%2F60+%29%2A%28+1%2F3.8+%29+=+10.965+ ALIGN=MIDDLE  ALT=\"+2500%2A%28+1%2F60+%29%2A%28+1%2F3.8+%29+=+10.965+\"   DISABLED_style= \"max-width:90%; height:auto;\" > gallons/minute </SPAN>\n" );
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