document.write( "Question 600388: how many grams of a 20% sulfuric acid solution must be mixed with 20 grams of a 35% sulfuric acid solution to make a 26% solution? \n" ); document.write( "
Algebra.Com's Answer #379329 by alicealc(293)![]() ![]() ![]() You can put this solution on YOUR website! let 20% sulfuric acid = x grams\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "20/100 * x + 35/100 * 20 = 26/100 * (x + 20) \n" ); document.write( "0.2x + 7 = 0.26*(x + 20) \n" ); document.write( "0.2x + 7 = 0.26x + 5.2 \n" ); document.write( "7 - 5.2 = 0.26x - 0.2x \n" ); document.write( "1.8 = 0.06x \n" ); document.write( "x = 1.8/0.06 = 180/6 = 30\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "so the 20% sulfuric acid needed is 30 grams\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |