document.write( "Question 600388: how many grams of a 20% sulfuric acid solution must be mixed with 20 grams of a 35% sulfuric acid solution to make a 26% solution? \n" ); document.write( "
Algebra.Com's Answer #379329 by alicealc(293)\"\" \"About 
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let 20% sulfuric acid = x grams\r
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\n" ); document.write( "\n" ); document.write( "20/100 * x + 35/100 * 20 = 26/100 * (x + 20)
\n" ); document.write( "0.2x + 7 = 0.26*(x + 20)
\n" ); document.write( "0.2x + 7 = 0.26x + 5.2
\n" ); document.write( "7 - 5.2 = 0.26x - 0.2x
\n" ); document.write( "1.8 = 0.06x
\n" ); document.write( "x = 1.8/0.06 = 180/6 = 30\r
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\n" ); document.write( "\n" ); document.write( "so the 20% sulfuric acid needed is 30 grams\r
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