document.write( "Question 600420: The monthly utility bills are normally distributed with a mean value of $160 and a standard deviation of $25.
\n" ); document.write( "(a) Find the probability of having a utility bill between 120 and 180.
\n" ); document.write( "(b) Find the probability of having a utility bill less than $120.
\n" ); document.write( "(c) Find the probability of having a utility bill more than $210.
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Algebra.Com's Answer #379326 by sniper619(1)\"\" \"About 
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a) P(120< x <180) = P( (120-160/25)< z < (180-160/25) )
\n" ); document.write( " = P( -1.6 < z < 0.8)
\n" ); document.write( " = P(z < 0.8) - P(z > 1.6)
\n" ); document.write( " = 0.7881 - (1-0.9452)
\n" ); document.write( " = 0.7881 - 0.0548
\n" ); document.write( " = 0.7333\r
\n" ); document.write( "\n" ); document.write( "b) P( x<120 ) = P( z < (120-160/25) )
\n" ); document.write( " = P( z < -1.6 )
\n" ); document.write( " = 1 - 0.9452
\n" ); document.write( " = 0.0548\r
\n" ); document.write( "\n" ); document.write( "c) P( x>210 ) = P( z > (210-160/25) )
\n" ); document.write( " = P( z > 2 )
\n" ); document.write( " = 1 - 0.9772
\n" ); document.write( " = 0.0228\r
\n" ); document.write( "\n" ); document.write( "Note: Used a Normal Distribution Function Table.
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