document.write( "Question 600406: factor the quadratic expression completely, and find the roots of the expression.\r
\n" ); document.write( "\n" ); document.write( "12x^2 +7x-12 \n" ); document.write( "
Algebra.Com's Answer #379317 by w_parminder(53)\"\" \"About 
You can put this solution on YOUR website!
\"12x%5E2%2B7x-12\"
\n" ); document.write( "Using the method of splitting the middle term, it can be written as
\n" ); document.write( "\"12x%5E2%2B16x-9x-12\"
\n" ); document.write( "OR
\n" ); document.write( "\"%28+12x%5E2%2B16x+%29-%28+9x%2B12+%29\" (taking out -ve sign common from the last two terms)
\n" ); document.write( "OR
\n" ); document.write( "\"4x%28+3x%2B4+%29-3%28+3x%2B4+%29\" (Taking out '4x' common from first two & '3' from last two terms)\r
\n" ); document.write( "\n" ); document.write( "Now (3x+4) is common in both terms, so the above expression can be written as
\n" ); document.write( "( 3x+4 )( 4x-3 )\r
\n" ); document.write( "\n" ); document.write( "these are the factors of the given expression\r
\n" ); document.write( "\n" ); document.write( "we can now find its roots by equating the factors with ZERO\r
\n" ); document.write( "\n" ); document.write( "i.e. 3x + 4 = 0
\n" ); document.write( "which gives x = -4/3\r
\n" ); document.write( "\n" ); document.write( "& 4x - 3 = 0
\n" ); document.write( "which gives x = 3/4\r
\n" ); document.write( "\n" ); document.write( "So the roots are -4/3 & 3/4
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