document.write( "Question 596611: how do you solve this?
\n" ); document.write( "-9=-2x^2+6x \n" ); document.write( "

Algebra.Com's Answer #379312 by dhartman0220(8) $\"\"$ $\"About$

You can put this solution on YOUR website!
-2x^2+6x+9=0 \r
\n" ); document.write( "\n" ); document.write( "its quadratic so either use the quadratic formula $\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"$
\n" ); document.write( "or complete the square....\r
\n" ); document.write( "\n" ); document.write( "factor out -2\r
\n" ); document.write( "\n" ); document.write( "-2(x^2-3x-9/2)=0 \r
\n" ); document.write( "\n" ); document.write( "x^2-3x=9/2
\n" ); document.write( "add 9/4 to both sides
\n" ); document.write( " x^2-3x+9/4=9/2 + 9/4\r
\n" ); document.write( "\n" ); document.write( "x^2-3x+9/4=[x-(3/2)]^2
\n" ); document.write( "so [x-(3/2)]^2 = 27/4\r
\n" ); document.write( "\n" ); document.write( "sqrt both sides x-(3/2) = (+-)sqrt(27/4)\r
\n" ); document.write( "\n" ); document.write( "sqrt(27/4)=3sqrt3/2\r
\n" ); document.write( "\n" ); document.write( "add 3/2 to both sides.....\r
\n" ); document.write( "\n" ); document.write( "x=[3(+-)3sqrt3]/2 \n" ); document.write( "

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