document.write( "Question 600379: Working together, two sisters can do the yard work at their house in 48 minutes. When the older girl does it all herself, she can complete the job in 20 minutes less time than it takes the younger girl working all alone. How long does it take the older girl to do the yard work? \n" ); document.write( "
Algebra.Com's Answer #379303 by josmiceli(19441) You can put this solution on YOUR website! Working together, their rate of working is: \n" ); document.write( "( 1 yard ) / ( 48 min ) \n" ); document.write( "Let \n" ); document.write( "younger girl to finish yard work \n" ); document.write( "--------- \n" ); document.write( "( 1 yard ) / ( t min ) = younger girls rate \n" ); document.write( "of working \n" ); document.write( "( 1 yard ) / ( t - 20 min ) = older girl's rate \n" ); document.write( "of working \n" ); document.write( "---------- \n" ); document.write( "Add their individual rates of working to get \n" ); document.write( "their rate working together \n" ); document.write( " \n" ); document.write( "Multiply both sides by \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Use quadratic formula \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "It takes the older girl 1 hr and 27 min working alone \n" ); document.write( "check: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "OK\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |