document.write( "Question 600376: A kitchen floor is 3 feet longer thann it is wide. The area of the floor is 180 square feet. Find the demensions of the kitchen.\r
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Algebra.Com's Answer #379287 by jim_thompson5910(35256)\"\" \"About 
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A = LW\r
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\n" ); document.write( "\n" ); document.write( "A = (W+3)W\r
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\n" ); document.write( "\n" ); document.write( "A = W(W+3)\r
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\n" ); document.write( "\n" ); document.write( "180 = W(W+3)\r
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\n" ); document.write( "\n" ); document.write( "180 = W^2 + 3W\r
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\n" ); document.write( "\n" ); document.write( "0 = W^2 + 3W - 180 \r
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\n" ); document.write( "\n" ); document.write( "W^2 + 3W - 180 = 0\r
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\n" ); document.write( "\n" ); document.write( "Now use the quadratic formula to solve for W\r
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\n" ); document.write( "\n" ); document.write( "W = (-b+-sqrt(b^2-4ac))/(2a)\r
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\n" ); document.write( "\n" ); document.write( "W = (-(3)+-sqrt((3)^2-4(1)(-180)))/(2(1))\r
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\n" ); document.write( "\n" ); document.write( "W = (-3+-sqrt(9-(-720)))/(2)\r
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\n" ); document.write( "\n" ); document.write( "W = (-3+-sqrt(729))/2\r
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\n" ); document.write( "\n" ); document.write( "W = (-3+sqrt(729))/2 or W = (-3-sqrt(729))/2\r
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\n" ); document.write( "\n" ); document.write( "W = (-3+27)/2 or W = (-3-27)/2\r
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\n" ); document.write( "\n" ); document.write( "W = 24/2 or W = -30/2\r
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\n" ); document.write( "\n" ); document.write( "W = 12 or W = -15\r
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\n" ); document.write( "\n" ); document.write( "Toss out the negative result to get the only answer of W = 12\r
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\n" ); document.write( "\n" ); document.write( "So the width is 12. \r
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\n" ); document.write( "\n" ); document.write( "The length is 3 more than the width. So the length is L = W+3 = 12+3 = 15\r
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\n" ); document.write( "\n" ); document.write( "The length is 15 feet and the width is 12 feet
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