document.write( "Question 600355: How can I find the height of a triangle that has a base of 10in. and a two sides that measure 13in? PLEASE HELP ME. \n" ); document.write( "
Algebra.Com's Answer #379286 by mamiya(56)\"\" \"About 
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Since two sides measures 13 in, that means we are talking about an isosceles triangle.\r
\n" ); document.write( "\n" ); document.write( "the height of that triangle is the distance between the midpoint of the base and the meeting point of the other two sides.
\n" ); document.write( " That height is perpendicular to the base ( because it is an isosceles triangle)\r
\n" ); document.write( "\n" ); document.write( "By applying the Pythagorean Theorem, we get
\n" ); document.write( " h^2 + (b\2)^2 = s^2 ( where h represents the height , b the base and s one of the other sides.
\n" ); document.write( " S0 we have h^2 = s^2 - (b/2)^2
\n" ); document.write( " = 13^2 - (10/2)^2
\n" ); document.write( " = 169 - 25
\n" ); document.write( " = 144\r
\n" ); document.write( "\n" ); document.write( " h^2 = 144 , so h = sqrt( 144) = 12\r
\n" ); document.write( "\n" ); document.write( "so the height is 12in
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