document.write( "Question 600355: How can I find the height of a triangle that has a base of 10in. and a two sides that measure 13in? PLEASE HELP ME. \n" ); document.write( "
Algebra.Com's Answer #379286 by mamiya(56)![]() ![]() ![]() You can put this solution on YOUR website! Since two sides measures 13 in, that means we are talking about an isosceles triangle.\r \n" ); document.write( "\n" ); document.write( "the height of that triangle is the distance between the midpoint of the base and the meeting point of the other two sides. \n" ); document.write( " That height is perpendicular to the base ( because it is an isosceles triangle)\r \n" ); document.write( "\n" ); document.write( "By applying the Pythagorean Theorem, we get \n" ); document.write( " h^2 + (b\2)^2 = s^2 ( where h represents the height , b the base and s one of the other sides. \n" ); document.write( " S0 we have h^2 = s^2 - (b/2)^2 \n" ); document.write( " = 13^2 - (10/2)^2 \n" ); document.write( " = 169 - 25 \n" ); document.write( " = 144\r \n" ); document.write( "\n" ); document.write( " h^2 = 144 , so h = sqrt( 144) = 12\r \n" ); document.write( "\n" ); document.write( "so the height is 12in \n" ); document.write( " |