document.write( "Question 600301: D=(n^2-3n) / 2
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\n" ); document.write( "Solve for n\r
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Algebra.Com's Answer #379277 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"D=%28n%5E2-3n%29%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "\"2D=n%5E2-3n\"\r
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\n" ); document.write( "\n" ); document.write( "\"0=n%5E2-3n-2D\"\r
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\n" ); document.write( "\n" ); document.write( "\"n%5E2-3n-2D=0\"\r
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\n" ); document.write( "\n" ); document.write( "Now use the quadratic formula to solve for 'n'. In this case, \"A=1\", \"B+=+-3\" and \"C=-2D\"\r
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\n" ); document.write( "\n" ); document.write( "\"n+=+%28-B+%2B-+sqrt%28+B%5E2-4AC+%29%29%2F%282A%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"n+=+%28-%28-3%29+%2B-+sqrt%28+%28-3%29%5E2-4%281%29%28-2D%29+%29%29%2F%282%281%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"n+=+%283+%2B-+sqrt%28+9+%2B+8D+%29%29%2F%282%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"n+=+%283+%2B+sqrt%28+9+%2B+8D+%29%29%2F%282%29\" or \"n+=+%283+-+sqrt%28+9+%2B+8D+%29%29%2F%282%29\"\r
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\n" ); document.write( "\n" ); document.write( "So the solutions are \"n+=+%283+%2B+sqrt%28+9+%2B+8D+%29%29%2F%282%29\" or \"n+=+%283+-+sqrt%28+9+%2B+8D+%29%29%2F%282%29\"
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