document.write( "Question 600343: What is 2m^2+9m+7=3 \n" ); document.write( "

Algebra.Com's Answer #379269 by w_parminder(53) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"2m%5E2%2B9m%2B7=3\"$
\n" ); document.write( "or $\"2m%5E2%2B9m%2B7-3=0\"$
\n" ); document.write( "or $\"2m%5E2%2B9m%2B4=0\"$
\n" ); document.write( "Now this quadratic equation can be solved using the formula
\n" ); document.write( " $\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"$ \r
\n" ); document.write( "\n" ); document.write( "But I solve it by splitting its middle term\r
\n" ); document.write( "\n" ); document.write( "So $\"2m%5E2%2B9m%2B4=0\"$ can be written as
\n" ); document.write( " $\"2m%5E2%2B8m%2Bm%2B4=0\"$
\n" ); document.write( "OR $\"%28+2m%5E2%2B8m+%29+%2B+%28+m%2B4+%29=0\"$
\n" ); document.write( "OR $\"2m%2A%28+m%2B4+%29+%2B+1%2A%28+m%2B4+%29\"$
\n" ); document.write( "OR $\"%28+m%2B4+%29%28+2m%2B1+%29=0\"$ \r
\n" ); document.write( "\n" ); document.write( "Now either (m + 4) = 0 OR (2m + 1) = 0
\n" ); document.write( "solving these equations we get,
\n" ); document.write( "m = -4 & m = -1/2\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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