document.write( "Question 600257: Jeremy is making a 665 mile trip. He drives for 5 hours at 55 mph. What is the average rate of speed he must drive to complete the total trip in 11 hours? Assume that a steady speed is maintained for the rest of the trip. \n" ); document.write( "
Algebra.Com's Answer #379266 by jim_thompson5910(35256)\"\" \"About 
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He drove 5 hours at 55 mph. So he drove d = rt = 55*5 = 275 miles so far.\r
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\n" ); document.write( "\n" ); document.write( "He now has 665 - 275 = 390 miles left to go\r
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\n" ); document.write( "\n" ); document.write( "So d = 390. \r
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\n" ); document.write( "\n" ); document.write( "Since he wants to complete the trip in 11 hours, and he's already taken up 5 hours, he has 11 - 5 = 6 hours left. \r
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\n" ); document.write( "\n" ); document.write( "So t = 6\r
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\n" ); document.write( "\n" ); document.write( "Now use d = rt to solve for r\r
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\n" ); document.write( "\n" ); document.write( "d = rt\r
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\n" ); document.write( "\n" ); document.write( "390 = r*6\r
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\n" ); document.write( "\n" ); document.write( "390/6 = r\r
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\n" ); document.write( "\n" ); document.write( "65 = r\r
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\n" ); document.write( "\n" ); document.write( "r = 65\r
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\n" ); document.write( "\n" ); document.write( "So he must average 65 mph
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