document.write( "Question 600259: How long does it take $100 to double it invested at 6% interest compounded continously? \n" ); document.write( "
Algebra.Com's Answer #379265 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"A=Pe%5E%28rt%29\" Start with the continuous compounding formula.\r
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\n" ); document.write( "\n" ); document.write( "\"200=100%2Ae%5E%280.06%2At%29\" Plug in \"A=200\", \"P=100\", and \"r=0.06\" (the decimal equivalent of 6%).\r
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\n" ); document.write( "\n" ); document.write( "\"200%2F100=e%5E%280.06%2At%29\" Divide both sides by \"100\".\r
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\n" ); document.write( "\n" ); document.write( "\"2=e%5E%280.06%2At%29\" Evaluate \"200%2F100\" to get \"2\".\r
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\n" ); document.write( "\n" ); document.write( "\"ln%282%29=ln%28e%5E%280.06%2At%29%29\" Take the natural log of both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"ln%282%29=0.06%2At%2Aln%28e%29\" Pull down the exponent using the identity \"ln%28x%5Ey%29=y%2Aln%28x%29%29\".\r
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\n" ); document.write( "\n" ); document.write( "\"ln%282%29=0.06%2At%2A1\" Evaluate the natural log of 'e' to get 1.\r
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\n" ); document.write( "\n" ); document.write( "\"ln%282%29=0.06%2At\" Multiply and simplify.\r
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\n" ); document.write( "\n" ); document.write( "\"0.693147180559945=0.06%2At\" Evaluate the natural log of \"2\" to get \"0.693147180559945\" (this value is approximate).\r
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\n" ); document.write( "\n" ); document.write( "\"0.693147180559945%2F0.06=t\" Divide both sides by \"0.06\" to isolate 't'.\r
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\n" ); document.write( "\n" ); document.write( "\"11.5524530093324=t\" Evaluate \"0.693147180559945%2F0.06\" to get \"11.5524530093324\".\r
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\n" ); document.write( "\n" ); document.write( "\"t=11.5524530093324\" Flip the equation.\r
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\n" ); document.write( "\n" ); document.write( "\"t=12\" Round to the nearest whole year.\r
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\n" ); document.write( "\n" ); document.write( "So it will take 12 years.
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