document.write( "Question 600262: Find three consecutive positive intergers such that the product of the first and second integers is 26 less than the product of the second and third.\r
\n" ); document.write( "\n" ); document.write( "i have no idea how to set this up! \n" ); document.write( "

Algebra.Com's Answer #379217 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let the 3 consecutive positive integers =
\n" ); document.write( " $\"+n+\"$
\n" ); document.write( " $\"+n+%2B+1+\"$
\n" ); document.write( " $\"+n+%2B+2+\"$
\n" ); document.write( "given:
\n" ); document.write( " $\"+n%2A%28+n+%2B+1+%29+=+%28+n+%2B+1+%29%2A%28+n+%2B+2+%29+-+26+\"$
\n" ); document.write( "---------
\n" ); document.write( " $\"+n%5E2+%2B+n+=+n%5E2+%2B+3n+%2B+2+-+26+\"$
\n" ); document.write( "Subtract $\"+n%5E2+\"$ from both sides
\n" ); document.write( " $\"+n+=+3n+%2B+2+-+26+\"$
\n" ); document.write( " $\"+n+=+3n+-+24+\"$
\n" ); document.write( " $\"+2n+=+24+\"$
\n" ); document.write( " $\"+n+=+12+\"$
\n" ); document.write( " $\"+n+%2B+1+=+13+\"$
\n" ); document.write( " $\"+n+%2B+2+=+14+\"$
\n" ); document.write( "The 3 consecutive positive integers are 12, 13, and 14
\n" ); document.write( "check:
\n" ); document.write( " $\"+n%2A%28+n+%2B+1+%29+=+%28+n+%2B+1+%29%2A%28+n+%2B+2+%29+-+26+\"$
\n" ); document.write( " $\"+12%2A13+=+13%2A14+-+26+\"$
\n" ); document.write( " $\"+156+=+182+-+26+\"$
\n" ); document.write( " $\"+156+=+156+\"$
\n" ); document.write( "OK \n" ); document.write( "

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