document.write( "Question 599990: The numerator of a fraction is 2 more than the denominator. If denominator is doubled at the numerator is decreased by 1, the sum of the original fraction and the new one is 7/3. Find the original fraction. \n" ); document.write( "
Algebra.Com's Answer #379148 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! The numerator of a fraction is 2 more than the denominator. \n" ); document.write( " If denominator is doubled and the numerator is decreased by 1, the sum of the original fraction and the new one is 7/3. \n" ); document.write( " Find the original fraction. \n" ); document.write( ": \n" ); document.write( "Let x = the denominator \n" ); document.write( "then \n" ); document.write( "(x+2) = the numerator \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "the equation for the statement: \n" ); document.write( "\"If denominator is doubled and the numerator is decreased by 1, the sum of the original fraction and the new one is 7/3.\" \n" ); document.write( " \n" ); document.write( "Multiply by 6x \n" ); document.write( "6x* \n" ); document.write( "cancel the denominators and you have \n" ); document.write( "3(x+1) + 6(x+2) = 2x(7) \n" ); document.write( "3x + 3 + 6x + 12 = 14x \n" ); document.write( "9x + 15 = 14x \n" ); document.write( "15 = 14x - 9x \n" ); document.write( "15 = 5x \n" ); document.write( "x = 15/5 \n" ); document.write( "x = 3 \n" ); document.write( ": \n" ); document.write( " |