document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=599450>Question 599450</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two cyclists start biking from a trail's start 3 hours apart. The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyclist who is traveling at 6 miles per hour. How much time will pass before the second cyclist catches up with the first from the time the second cyclist started biking? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #379147 by </B><A HREF=/tutors/aboutme.mpl?userid=dhartman0220><B>dhartman0220(8)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dhartman0220><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=379147\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Distance is equal to velocity multiplied by time   D=v*t\r<BR>\n" );
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document.write( "The distance traveled by the second biker will equal the distance traveled by the first at some point in time.\r<BR>\n" );
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document.write( "hence D1=first cyclist<BR>\n" );
document.write( "                    v=6(m/h)<BR>\n" );
document.write( "                    t=(3+x)h<BR>\n" );
document.write( "            D2=second cyclist<BR>\n" );
document.write( "                    v=10(m/h)<BR>\n" );
document.write( "                    t=xh\r<BR>\n" );
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document.write( "we know D1 is 3 hours ahead and D2 has to travel (x) amount of time to catch up. \r<BR>\n" );
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document.write( "so\r<BR>\n" );
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document.write( "D1=D2\r<BR>\n" );
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document.write( "6(3+x)=10x\r<BR>\n" );
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document.write( "18+6x=10x\r<BR>\n" );
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document.write( "18=4x\r<BR>\n" );
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document.write( "x=4.5 hours </SPAN>\n" );
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