document.write( "Question 599931: what is the way to solve the logarithms a.) 2e^9x=4 b.)ln(4x − 3) = 4 and c.)
\n" ); document.write( "7^x + 1 = 4? I keep getting a negative answer fot c. and I know it is not supposed to be that way. I am getting depressed. Can you please help? ex.:
\n" ); document.write( "7^x+1=4, log7^x+1=4, (x+1)log7=log4, xlog7+log7=log4-log7, x=log4-log7/log7. All my answers are negatives, and are wrong. \n" ); document.write( "
Algebra.Com's Answer #379135 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
a.) 2e^9x=4
\n" ); document.write( "e^9x=4/2=2
\n" ); document.write( "take log of both sides
\n" ); document.write( "9xlne=ln2
\n" ); document.write( "lne=1
\n" ); document.write( "9x=ln2
\n" ); document.write( "x=ln2/9
\n" ); document.write( "x≈0.077
\n" ); document.write( "..
\n" ); document.write( "b.)ln(4x − 3) = 4
\n" ); document.write( "convert to exponential form: base(e) raised to log of number(4)=number(4x-3)
\n" ); document.write( "e^4=4x-3
\n" ); document.write( "4x=e^4+3
\n" ); document.write( "x=(e^4+3)/4
\n" ); document.write( "x≈14.4
\n" ); document.write( "..
\n" ); document.write( "c.)7^x + 1 = 4
\n" ); document.write( "7^x=3
\n" ); document.write( "xlog7=log3
\n" ); document.write( "x=log3/log7
\n" ); document.write( "x≈0.564 \n" ); document.write( "
\n" );