document.write( "Question 599933: find 3 consecutive integers such that the product of the 2 larger integers is 50 more than 5 times the smallest integer. \n" ); document.write( "

Algebra.Com's Answer #379133 by Nihal@SriLanka(22) $\"\"$ $\"About$

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let's assume the integers are x, x+1 and x+2 respectively.\r
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\n" ); document.write( "\n" ); document.write( "We are given that (x+1)(x+2) = 50 + 5x\r
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\n" ); document.write( "\n" ); document.write( "We proceed to solve this equation as follows\r
\n" ); document.write( "\n" ); document.write( " (x+1)(x+2) = 50 + 5x
\n" ); document.write( "i.e. x^2 + 3x + 2 = 50 + 5x
\n" ); document.write( "i.e. x^2 - 2x + 48 = 0
\n" ); document.write( "i.e. (x - 8)(x - 6)= 0
\n" ); document.write( "i.e. x = 8 or -6\r
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\n" ); document.write( "\n" ); document.write( "Hence the required numbers are 8,9 and 10 or -6,-5 and -4 counting negative integers as well. \n" ); document.write( "

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