document.write( "Question 599778: I'm a whole number greater than 1. Multiply me by 3 and the produxt is less than 20. Divide me by 3 and the remainder is 1. What number am I? \n" ); document.write( "
Algebra.Com's Answer #379085 by Edwin McCravy(20067)\"\" \"About 
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document.write( "The other tutor's answer is wrong because the\r\n" );
document.write( "clue says it's greater than 1, so it can't be 1.\r\n" );
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document.write( "The clue:\r\n" );
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document.write( "\"Multiply me by 3 and the product is less than\r\n" );
document.write( "20.\"\r\n" );
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document.write( "Since 3 times 7 = 21 tells us that it's 6 or\r\n" );
document.write( "less\r\n" );
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document.write( "The clue:\r\n" );
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document.write( "\"I'm a whole number greater than 1.\"\r\n" );
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document.write( "Now we know it's one of these\r\n" );
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document.write( "6,5,4,3,2\r\n" );
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document.write( "The clue \"Divide me by 3 and the remainder is 1\".\r\n" );
document.write( "So we divide all the possibilities by 3 and look at the\r\n" );
document.write( "remainders:\r\n" );
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document.write( "  2      1      1      1      0\r\n" );
document.write( "3)6    3)5    3)4    3)3    3)2\r\n" );
document.write( "  6      3      3      3      0\r\n" );
document.write( "  0      2      1      0      2\r\n" );
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document.write( "We see that 4 is the only one that has a remainder of 1 \r\n" );
document.write( "when divided by 3.\r\n" );
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document.write( "So the answer is 4.\r\n" );
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document.write( "Edwin
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