document.write( "Question 599772: log7(3-4x)=log7(x/3) \n" ); document.write( "
Algebra.Com's Answer #379063 by stanbon(75887)\"\" \"About 
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log7(3-4x)=log7(x/3)
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\n" ); document.write( "3-4x = x/3
\n" ); document.write( "4x + (x/3) = 3
\n" ); document.write( "12x + x = 9
\n" ); document.write( "13x = 9
\n" ); document.write( "x = 9/13
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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